L01 Introduction & Preliminaries

Introduction to Financial Instruments

Interest Rate & Bond Fundamentals

Compound Interest

A(1+Rmm)mnA\left(1+\frac{R_m}{m}\right)^{mn}

Zero Rates

Bond Pricing

The idea: To calculate the cash price of a bond we discount each cash flow at the appropriate zero rate.

The Pricing Formula
B={t=1TCt(1+Rt)t+F(1+RT)T(simple interest)t=1TCteRtt+FeRTT(continuously compounded)B=\left\{\begin{array}{ll} \sum_{t=1}^{T}\frac{C_{t}}{\left(1+R_{t}\right)^{t}}+\frac{F}{\left(1+R_{T}\right)^{T}} & \text{(simple interest)}\\ \sum_{t=1}^{T}C_{t}e^{-R_tt}+Fe^{-R_TT} & \text{(continuously compounded)} \end{array}\right.
Example: A 2-year Treasure bond with a principal if $100 provides coupon at the rate of 6% per annum semiannually. The zero rates are quoted with continuous pompounding.

Maturity (years) Zero rate (%)
0.5 5.0
1.0 5.8
1.5 6.4
2.0 6.8

3e0.05×0.5+3e0.058×1.0+3e0.064×1.5+103e0.068×2.0=98.393e^{-0.05\times0.5}+3e^{-0.058\times1.0}+3e^{-0.064\times1.5}+103e^{-0.068\times2.0}=98.39

Bound Yield

Bond yield is the single discount rate that, when applied to all cash flows, gives a bond price equal to its market price.
B=t=1TCtety+FeTyB=\sum_{t=1}^{T}C_{t}e^{-ty}+Fe^{-Ty}

Example: Suppose the market price of the bond is $98.39, please determine the yield to maturity.

3ey×0.5+3ey×1.0+3ey×1.5+103ey×2.0=98.393e^{-y\times0.5}+3e^{-y\times1.0}+3e^{-y\times1.5}+103e^{-y\times2.0}=98.39
Solving yy, we have y=6.76%y=6.76\%.

(Macaulay's) Duration

Modified Duration

Modified Duration is defined as D=D1+y/mD^*=\frac{D}{1+y/m}. It allows us to simplify ΔB\Delta B.

Generally, if yy is expressed with a compounding frequency of mm times per year, then

ΔB=BDΔy1+y/m=BDΔy\Delta B=-\frac{BD\Delta y}{1+y/m}=-BD^*\Delta y

Bond Portfolios

Convexity

A measure of convexity is
C=1Bd2Bdy2=i=1nciti2eytiBC=\frac{1}{B}\frac{d^2B}{dy^2}=\frac{\sum_{i=1}^nc_it_i^2e^{-yt_i}}{B}

Approximate ΔB\Delta B with the first two oder derivatives of the interest rate.
ΔBB=DΔy+12C(Δy)2\frac{\Delta B}{B}=-D\Delta y+\frac{1}{2}C(\Delta y)^2
When used for bond portfolios it allows larger shifts in the yield curve to be considered, but the shifts still have to be parallel

Equities

Gordon Growth Model

Systematic Risk & Nonsystematic Risk

Measuring Systematic Risk: Beta

The Market Model: Ri=αi+βiRm+eiR_i=\alpha_i+\beta_iR_m+e_i. We have,
Cov(Ri,Rm)=Cov(αi+βiRm+ei,Rm)=Cov(Rf(1βi)+βiRm+ei,Rm)=βiCov(Rm,Rm)+βiCov(ei,Rm)=βiσm2\begin{array}{lll} Cov(R_i,R_m)&=&Cov(\alpha_i+\beta_iR_m+e_i,R_m)\\ &=&Cov\left(R_f\left(1-\beta_i\right)+\beta_iR_m+e_i,R_m\right)\nonumber\\ &=&\beta_iCov(R_m,R_m)+\beta_iCov(e_i,R_m)\nonumber\\ &=&\beta_i\sigma_m^2 \end{array}
So, theoretically the beta can be calculated as below.
βi=σi,m2σm2=σiσmρi,m\beta_i=\frac{\sigma_{i,m}^2}{\sigma_m^2}=\frac{\sigma_i}{\sigma_m}\rho_{i,m}\nonumber

CAPM: The Security Market Line (SML)

E[Ri]Rf=βi(E[Rm]Rf)E[R_i]-R_f=\beta_i(E[R_m]-R_f)

Arbitrage Pricing Theory (APT)}

The expected return on any asset ii (E[Ri]E[R_i]) can be expressed as:
E[Ri]=λ0+λ1bi1+λ1bi2+++λ1bik (APT)E[R_i]=\lambda_0+\lambda_1b_{i1}+\lambda_1b_{i2}+\dots++\lambda_1b_{ik}\text{ (APT)}

Understanding APT

Forwards and Futures

FORWARDS FUTURES
Private contracts between 2 parties Traded on an exchange
Not standardized Standardized contracts
Usually on specified delivery date Range of delivery dates
Settled at end of contracts Settled daily
Delivery or final cash settlement usually takes place Contracts usually closed out prior to maturity
Some credit risk Virtually no credit risk

Pricing: No-arbitrage Argument}

Option

An option is a contract which gives the buyer (the owner) the right, but not the obligation, to buy or sell an underlying asset or instrument at a specified strike price on or before a specified date.

Payoff (Diagram)

call put
long max(STK,0)\max(S_T-K,0) max(KST,0)\max(K-S_T,0)
short max(STK,0)-\max(S_T-K,0) max(KST,0)-\max(K-S_T,0)

Option Pricing: The Black-Scholes Formula

Understanding Black-Scholes

The formula
c=erTN(d2)(S0erTN(d1)/N(d2)K)c=e^{-rT}N(d_2)\left(S_0e^{rT}N(d_1)/N(d_2)-K\right)
- erTe^{-rT}: Discount factor
- N(d2)N(d_2): Probability of exercise
- erTN(d1)/N(d2)e^{rT}N(d_1)/N(d_2): Expected percentage increase in stock price if option is exercised
- KK: Strike price paid if option is exercised

Introduction to Financial Risk Mamagement

Managing Linar Risk

Hedge}

Hedge Horizon and Contract Maturity

Basis Risk

Long Hedge

Short Hedge

Choice of Contract

Cross Hedging

Tailing the Hedge}

Example

An airline knows that it will need to purchase 10,000 metric tons of jet fuel in three months. It wants some protection against an upturn in prices using futures contracts.

The company can hedge using heating oil futures contracts traded on NYMEX. The notional for one contract is 42,000 gallons. As there is no futures contract on jet fuel, the risk manager wants to check if heating oil could provide an efficient hedge instead. The current price of jet fuel is $277/metric ton. The futures price of heating oil is $0.6903/gallon. The standard deviation of the rate of Change in jet fuel prices over three months is 21.17%, that of futures is 18.59%, and the correlation is 0.8243.

Compute:

  1. The notional and standard deviation of the unhedged fuel cost in dollars

  2. The optimal number of futures contract to buy/sell, rounded to the closest integer

Solution:

  1. The position notional is QS=$2,770,000Q_S=\$2,770,000. The standard deviation in dollars is
    σ(Δs/s)sQ=0.2117×$277×10,000=$586,409\sigma(\Delta s/s)sQ=0.2117\times\$277\times10,000=\$586,409
    For reference, that of one futures contract is
    σ(Δf/f)fQf=0.1859×$0.6903×42,000=$5,389.72\sigma(\Delta f/f)fQ_f=0.1859\times\$0.6903\times42,000=\$5,389.72
    with a future notional of Qf=$0.6903×42,000=$28,992.60Q_f=\$0.6903\times42,000=\$28,992.60.

  2. The cash position corresponds to a payment, or liability. Hence, the company will have to buy futures as protction. First, we compute the optimal hedge ration:
    h=ρS,FσΔSσΔF=0.8243×0.21170.1859=0.9387h^*=\rho_{S,F}\frac{\sigma_{\Delta S}}{\sigma_{\Delta F}}=0.8243\times\frac{0.2117}{0.1859}=0.9387
    Then the number of furtures contract required is
    N=hVAVF=0.9387×10,000×$27742,000×$0.69=89.790N^*=\frac{h^*V_A}{V_F}=\frac{0.9387\times10,000\times\$277}{42,000\times\$0.69}=89.7\approx90

Hedging Using Index Futures

To hedge the risk in a portfolio the number of contracts that should be shorted is

N=βPFN^*=\beta\frac{P}{F}

where PP is the value of the portfolio, β\beta is its beta, and FF is the value of one futures contract

Changing β\beta

Example

A portfolio manager holds a stock portfolio worth $10 million with a beta of 1.5 relative to the S&P 500. The current futures price is 1,400, with a multiplier of $250.

Compute:

  1. The notional of the futures contract

  2. The number of contracts to sell short for optimal protection

Solution:

  1. The notional amount of the futures contract is $250×1,400=$350,000\$250\times1,400 = \$350,000.

  2. The optimal number of contracts to short is,
    N=βPF=1.5×$10,000,000$350,000=42.943N^*=\beta\frac{P}{F}=1.5\times\frac{\$10,000,000}{\$350,000}=42.9\approx43

Nonlinear (Option) Risk Models

Option Sensitivities

Taylor Expansion
df=fSdS+122fS2dS2+frdr+frdr+fσdσ+fτdτ+df=\frac{\partial f}{\partial S}dS+\frac{1}{2}\frac{\partial^2 f}{\partial S^2}dS^2+\frac{\partial f}{\partial r}dr+\frac{\partial f}{\partial r^*}dr^*+\frac{\partial f}{\partial \sigma}d\sigma+\frac{\partial f}{\partial \tau}d\tau+\dots